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Period 3 Reactions with Chlorine

UNIT 2 CHEMISTRY · PEARSON AAQ · C1.3.3

Period 3 Reactions with Chlorine

FREE CHEMISTRY REVISION · TOPIC 25

Follow the specified products from ionic lattices to covalent molecules.

Compare five chlorine reactions, interpret Al₂Cl₆ accurately, and separate formal oxidation numbers from real bonding.

Pearson BTEC Level 3 AAQ Applied Science
Unit 2: Principles and Applications of Chemistry · C1.3.3

What you will learn

Compare the reactions of sodium, magnesium, aluminium, silicon and phosphorus with chlorine, using the five products specified in C1.3.3: NaCl, MgCl₂, Al₂Cl₆, SiCl₄ and PCl₅. Describe visible observations, balance equations and connect bonding and structure to the metal-to-non-metal transition.

The product formula is fixed for this lesson. In particular, retain the dimer formula Al₂Cl₆ when representing molecular aluminium chloride, and use PCl₅ for phosphorus in excess chlorine. Other chlorides are not extra required products for this specification point.

1. Chlorine as an oxidising agent

Elemental chlorine is a pale green/yellow-green, diatomic gas, Cl₂. In the specified chlorides, its oxidation number is −1. Chlorine is therefore reduced in these reactions, while the Period 3 element is oxidised from zero to a positive oxidation number.

The formal reduction half-equation is Cl₂ + 2e⁻ → 2Cl⁻. It is useful for redox accounting, but does not mean that every product is a collection of simple metal and chloride ions. In covalent SiCl₄ and molecular Al₂Cl₆, oxidation numbers are formal bookkeeping; the bonded atoms share electron density.

Observations below describe controlled demonstrations, not experimental instructions. A bright flame, a white solid and the loss of chlorine colour are distinct observations. Moist-air fumes from a chloride are not automatically the colour of the pure compound.

2. Sodium and magnesium: ionic chlorides

Sodium: once a reaction is initiated, sodium reacts vigorously with chlorine with a bright yellow/orange-yellow flame. White sodium chloride forms. The equation is 2Na(s) + Cl₂(g) → 2NaCl(s). Each sodium atom changes from 0 to +1 and each chlorine atom from 0 to −1.

NaCl is a giant ionic lattice with a 1:1 ratio of Na⁺ and Cl⁻. Its formula gives the simplest ion ratio, not a separate NaCl molecule. Ionic bonds are electrostatic attractions throughout the lattice, rather than isolated sticks connecting one pair of atoms.

Magnesium: heated magnesium reacts vigorously with chlorine, producing a bright white light and white magnesium chloride. Mg(s) + Cl₂(g) → MgCl₂(s). One magnesium atom supplies two electrons in the formal transfer picture, balancing the two electrons accepted by a Cl₂ molecule.

MgCl₂ contains Mg²⁺ and Cl⁻ in a 1:2 ratio. Its larger subscript does not mean that it has two chlorine molecules per magnesium atom: it has two chlorine atoms, corresponding to two chloride ions, per magnesium ion.

Ionic formula ratios, not discrete moleculesCharge balance in ionic chloridesNa⁺Cl⁻1 positive charge + 1 negative charge → NaClMg²⁺Cl⁻Cl⁻2 positive charges + 2 negative charges → MgCl₂
The separated symbols show the charge-balanced ratio only. Both salts form extended lattices, not these isolated clusters. Ion radii and separation are not to scale.

3. Aluminium: keep the Al₂Cl₆ molecular representation

When initiated, aluminium reacts with chlorine to produce aluminium chloride. The reaction can be vigorous, with glowing/bright burning metal and a white deposit or fumes. The protective oxide film can delay the reaction of bulk aluminium; surface condition matters.

2Al(s) + 3Cl₂(g) → Al₂Cl₆
Product formula specified in C1.3.3; the product phase depends on temperature.

The empirical ratio is AlCl₃, but Al₂Cl₆ is the dimeric molecular representation required here. Two aluminium centres are connected by two bridging chlorine atoms; each aluminium also has two terminal chlorine atoms. There are six chlorine atoms altogether: four terminal and two bridging.

Aluminium’s small, highly charged centre strongly polarises chlorine’s electron cloud, giving substantial covalent character. Do not draw the molecular dimer as two isolated Al³⁺ ions beside six isolated Cl⁻ ions. Anhydrous solid aluminium chloride has an extended structure; its structure is phase-dependent and is not simply a collection of the same dimers in every state. The dimer is important in the liquid and lower-temperature vapour; at higher vapour temperatures it dissociates towards AlCl₃ monomers.

Connectivity of the Al₂Cl₆ dimerAlAlClClClClClClTwo bridging Cl atomsFour outer Cl atoms are terminal.Connectivity sketch: bond angles and lengths not to scale.
Every bridge connects both Al centres. Lines represent covalent connectivity, including the bridging interactions; this is not a dot-and-cross diagram or a planar molecular geometry claim. Each aluminium centre has four chlorine neighbours in the dimer.

4. Silicon and phosphorus: specified covalent formulae

Silicon: heated silicon reacts with chlorine, forming silicon tetrachloride: Si(s) + 2Cl₂(g) → SiCl₄(l), with the product state shown after cooling to room temperature. The reaction can give a glow/burning solid. SiCl₄ itself is a colourless volatile liquid; it fumes in damp air because it reacts with moisture, not because pure SiCl₄ is a white solid.

SiCl₄ consists of discrete tetrahedral molecules, each with four Si–Cl covalent bonds and a Cl–Si–Cl angle of approximately 109.5°. Silicon has oxidation number +4, but this does not indicate free Si⁴⁺ ions in a chloride lattice.

Phosphorus: phosphorus reacts vigorously with chlorine. In excess chlorine, the specified phosphorus(V) chloride product is represented by P₄(s) + 10Cl₂(g) → 4PCl₅(s), with the product state after cooling. A bright flame and white solid/fumes can be observed. Product proportions depend on the chlorine supply, so specify excess chlorine when identifying PCl₅.

The P₄ reactant equation is a convenient molecular representation; red phosphorus is an extended allotrope and should not be described as a solid made of independent P₄ molecules.

PCl₅ is phase-dependent. A discrete gaseous PCl₅ molecule is trigonal bipyramidal. Solid PCl₅ is ionic, containing tetrahedral [PCl₄]⁺ and octahedral [PCl₆]⁻ ions. Two formula units give one of each ion: 2PCl₅ corresponds to [PCl₄]⁺[PCl₆]⁻. Neither this pair nor the gas should be labelled P⁵⁺ surrounded by five independent Cl⁻ ions.

5. Trends and observations at a glance

Five specified chlorine reactions
ElementBalanced equationTypical observationBonding reminder
Na2Na + Cl₂ → 2NaClYellow flame; white saltIonic Na⁺/Cl⁻ lattice
MgMg + Cl₂ → MgCl₂Bright white light; white solidIonic Mg²⁺/Cl⁻ lattice
Al2Al + 3Cl₂ → Al₂Cl₆Vigorous reaction after initiation; white deposit/fumesUse covalent dimer for molecular representation; structure depends on phase
SiSi + 2Cl₂ → SiCl₄Heated silicon reacts; colourless product liquid after coolingDiscrete tetrahedral molecules
PP₄ + 10Cl₂ → 4PCl₅Vigorous burning; white product in excess chlorineMolecular vapour; complex ionic solid

Across the set, the formal oxidation number of the Period 3 element rises +1, +2, +3, +4, +5. Covalent character becomes important as the electronegativity difference with chlorine narrows; aluminium’s polarising effect is significant. This is not a simple monotonic reaction-rate graph. Temperature, surface films, allotrope and chlorine supply affect observations.

6. Four worked examples

Example 1 — balance aluminium’s dimer equation

Question: Balance Al + Cl₂ → Al₂Cl₆ using the specified product.

Step 1: Al₂Cl₆ contains two Al atoms, so put 2 before Al. Step 2: Six Cl atoms require three Cl₂ molecules. Answer: 2Al + 3Cl₂ → Al₂Cl₆. Do not replace the molecular product by AlCl₃ when the question specifically requests Al₂Cl₆.

Example 2 — phosphorus with excess chlorine

Question: Balance P₄ + Cl₂ → PCl₅.

Step 1: The four P atoms require 4PCl₅. Step 2: These contain 20 Cl atoms, requiring 10Cl₂. Answer: P₄ + 10Cl₂ → 4PCl₅. Each P changes 0 → +5, giving a total increase of 20; 20 Cl atoms each decrease 0 → −1.

Example 3 — interpret silicon’s product

Question: A heated Period 3 element reacts with chlorine to form SiCl₄. Why is a diagram of Si⁴⁺ and four free Cl⁻ ions misleading?

Step 1: The +4 value is a formal oxidation number. Step 2: SiCl₄ has shared Si–Cl bonding in discrete tetrahedral molecules. Answer: depict a silicon centre covalently bonded to four Cl atoms, not an ionic lattice.

Example 4 — test a dimer drawing

Question: A proposed Al₂Cl₆ drawing has two Al atoms, two bridging Cl atoms and six terminal Cl atoms. Is it correct?

Step 1: Count all chlorine atoms: 2 + 6 = 8. Step 2: Al₂Cl₆ requires six in total. Answer: use two bridging and four terminal Cl atoms. Each Al then has two terminal and two bridging chlorine neighbours.

Common misconceptions

  • “All chlorides of these elements are simple ionic compounds.” SiCl₄ is molecular; Al₂Cl₆ is a covalent dimer; PCl₅ has phase-dependent structure.
  • “Al₂Cl₆ has six terminal Cl atoms plus two bridges.” It has four terminal and two bridging chlorine atoms in total.
  • “PCl₅ is molecular in every state.” The solid contains [PCl₄]⁺ and [PCl₆]⁻ ions.
  • “The white fumes from a moist-air reaction prove that SiCl₄ is a white solid.” Pure SiCl₄ is a colourless liquid at room temperature; moisture changes the chemical species.
  • “A higher oxidation number proves faster reaction.” It records electron accounting, not rate.

Exam tips

  • Start from Cl₂, not individual chlorine atoms, when balancing an element–chlorine equation.
  • State excess chlorine for the specified PCl₅ product.
  • Distinguish flame colour, product colour and moist-air fumes.
  • Use Al₂Cl₆ when requested; its empirical ratio is AlCl₃.
  • Explain bonding with reference to phase, especially for aluminium chloride and PCl₅.

Check your understanding

Select one option and Check Answer. Read the explanation, then use Try Again to reset.

Question 1 of 5 · Unit 2 C1.3.3

Which equation forms the specified aluminium chloride dimer?

Question 2 of 5 · Unit 2 C1.3.3

How many terminal and bridging chlorine atoms are in one Al₂Cl₆ dimer?

Question 3 of 5 · Unit 2 C1.3.3

What is the bonding and shape of a discrete SiCl₄ molecule?

Question 4 of 5 · Unit 2 C1.3.3

Which statement correctly describes phosphorus(V) chloride?

Question 5 of 5 · Unit 2 C1.3.3

In P₄ + 10Cl₂ → 4PCl₅, how do the oxidation numbers change?

Scope checked against Pearson BTEC Level 3 AAQ Applied Science, Issue 7, May 2026, Unit 2 C1.3.3, printed page 38. Official Pearson specification (PDF).

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