BTECRevision

Period 3 Reactions with Oxygen

UNIT 2 CHEMISTRY · PEARSON AAQ · C1.3.1

Period 3 Reactions with Oxygen

FREE CHEMISTRY REVISION · TOPIC 23

Explain the observations while keeping the specified products fixed.

Compare five Period 3 oxygen reactions using balanced equations, original labelled diagrams, redox accounting and bonding explanations.

Pearson BTEC Level 3 AAQ Applied Science
Unit 2: Principles and Applications of Chemistry · C1.3.1

What you will learn

Describe and explain the reactions of sodium, magnesium, aluminium, phosphorus and sulfur with oxygen, using the products specified in Pearson C1.3.1: Na₂O, MgO, Al₂O₃, P₄O₁₀ and SO₂ only. Write balanced equations, distinguish observations from explanations and connect the reactions to electronic structure, bonding and redox.

1. The scope and the reaction model

An oxide contains oxygen combined with another element. These oxygen reactions are oxidation reactions: the Period 3 element is oxidised and oxygen is reduced. Each starts as an uncombined element with oxidation number 0; oxygen is −2 in all five specified products.

Use the product stated in the specification or examination question. For sodium, the required model product here is Na₂O. Actual combustion can yield a mixture whose composition depends on conditions; do not claim that every sodium-burning experiment produces pure Na₂O. This lesson keeps the reaction equations to Pearson’s five specified products.

The observations below are typical descriptions of controlled demonstrations, not instructions to carry them out. Product appearance, flame colour and ease of ignition are distinct observations; the chemical equation explains composition, not the precise brightness of a flame.

2. Sodium, magnesium and aluminium

Sodium: a freshly exposed metallic surface tarnishes as it reacts with oxygen-containing air. On burning it gives a yellow/orange-yellow flame. Sodium oxide itself is a white solid. For the required product, write 4Na(s) + O₂(g) → 2Na₂O(s). Na changes 0 → +1; four Na atoms lose four electrons in the ionic accounting, while the two O atoms gain four electrons in total.

Magnesium: once ignited, it burns with an intense white light and forms white MgO ash/powder: 2Mg(s) + O₂(g) → 2MgO(s). Mg changes 0 → +2. Two Mg atoms lose four electrons; oxygen gains four. The white light is an observation of the burning process; the white solid is the product.

Aluminium: bulk metal is protected by an adherent oxide film, so it can appear unreactive in ordinary air. Finely divided aluminium, when strongly heated and initiated, can burn with bright white sparks, producing white Al₂O₃: 4Al(s) + 3O₂(g) → 2Al₂O₃(s). Al changes 0 → +3. The film changes the reaction rate and access to the surface; it does not mean aluminium has no tendency to react with oxygen.

Cross-section of passivated aluminium with oxygen outside the oxide layerAluminium: a thin oxide film limits further reactionO₂ molecules above the surfaceOOOOOOAl metal beneath the filmlimited oxygen accessPurple band: adherent Al₂O₃ layer (not to scale)Fine particles + strong heating can burn with white sparks.Surface area and activation energy affect what is observed.
The oxide film is thin, adherent and protective. Incoming oxygen arrows stop above the film; the sketch does not imply oxygen flows freely into the metal. The drawn thickness is exaggerated. Bulk aluminium can appear resistant while finely divided aluminium can react vigorously once initiated.

3. Phosphorus and sulfur

Phosphorus: burning produces a bright white to yellow-white/orange flame and dense white smoke/fumes of condensed oxide particles. With sufficient oxygen the specified product is phosphorus(V) oxide, P₄O₁₀: P₄(s) + 5O₂(g) → P₄O₁₀(s). Each P changes 0 → +5 and each O changes 0 → −2. The four P atoms have a total oxidation-number increase of 20, matching the total oxygen decrease of 20.

Phosphorus has allotropes with different ease of ignition. White phosphorus contains P₄ molecules; red phosphorus has an extended structure and needs stronger initiation. The P₄ equation is the convenient molecular representation used here; it must not be read as a claim that red phosphorus consists of separate P₄ molecules. Retain the specified product P₄O₁₀ rather than substituting its empirical ratio P₂O₅ in a molecular-formula answer.

Sulfur: burns with a blue flame and produces colourless sulfur dioxide gas, SO₂. It is not a white solid smoke. The usual per-sulfur-atom equation is S(s) + O₂(g) → SO₂(g); an equivalent molecular equation for S₈ is S₈(s) + 8O₂(g) → 8SO₂(g). Each S changes 0 → +4. SO₂ has a characteristic choking odour, but smelling it is not an appropriate identification test.

The non-metal oxides involve covalent bonding. SO₂ consists of discrete bent molecules; the common molecular form of P₄O₁₀ contains covalent cages. Formal positive oxidation numbers on P and S do not imply the presence of free P⁵⁺ or S⁴⁺ ions.

4. Compare the five specified reactions

Observations, equations and redox changes
Element / conditionTypical observationSpecified equationElement oxidation number
Na: burning; Na₂O modelYellow/orange-yellow flame; oxide itself white4Na + O₂ → 2Na₂O0 → +1
Mg: ignitedIntense white light; white solid2Mg + O₂ → 2MgO0 → +2
Al: fine particles, initiatedWhite sparks; white oxide; bulk protected4Al + 3O₂ → 2Al₂O₃0 → +3
P: sufficient oxygenBright flame; dense white smokeP₄ + 5O₂ → P₄O₁₀0 → +5
S: burningBlue flame; colourless gasS + O₂ → SO₂0 → +4

In each case O changes 0 → −2 and O₂ acts as the oxidising agent. The element reacting with oxygen acts as the reducing agent. In covalent products, oxidation numbers describe formal electron allocation; in simple ionic oxides the ion model makes electron loss/gain especially direct.

5. What periodicity explains—and what the observations depend on

Na, Mg and Al have valence configurations [Ne]3s¹, [Ne]3s² and [Ne]3s²3p¹. Their common oxide compositions reflect +1, +2 and +3 oxidation states with oxygen at −2. Across the period, increasing effective nuclear attraction generally makes electron removal harder and metallic/electropositive character declines. Bonding to oxygen becomes increasingly covalent towards the non-metal side.

Na₂O and MgO are described as extended ionic solids. Al₂O₃ is also an extended lattice with strong ionic interactions and appreciable covalent character. The small, highly charged Al centre polarises oxide electron density, so an entirely non-polarised ion model is a simplification. P₄O₁₀ and SO₂ use covalent bonding rather than simple monatomic cations surrounded by oxide ions.

Do not infer a smooth numerical reactivity trend from flame colours or assume that every successive element burns less vigorously. Observed behaviour also depends on activation energy, the bonds and structures of the reactants, surface area, allotrope, temperature, oxygen supply and protective films. Aluminium passivation is a clear example of a kinetic barrier masking a favourable reaction.

These reactions release energy overall because product formation releases more energy than is needed to disrupt the reactants’ bonding. Breaking bonds requires energy; it does not itself cause the release. An exothermic reaction may still need ignition to overcome its activation barrier. The product oxidation numbers also need not rise smoothly: P is +5 in the specified oxide while S is +4 in SO₂.

Schematic extended magnesium oxide lattice and bent sulfur dioxide moleculeMetal oxide versus non-metal molecular oxideMgO: extended ionic lattice (2D slice)Mg²⁺O²⁻Mg²⁺O²⁻O²⁻Mg²⁺O²⁻Mg²⁺Mg²⁺O²⁻Mg²⁺O²⁻Alternating ions; the lattice continues in 3D.SO₂: a discrete, bent covalent moleculeSOO~119°S—O connectivity only; electron pairs / bond order omitted.
The MgO slice shows six Mg²⁺ and six O²⁻ ions, giving a 1:1 ratio; it is not a complete coordination diagram. SO₂ is shown in its molecular plane. Its links indicate connectivity, not a full Lewis or resonance representation. Oxidation number +4 on sulfur does not mean a free S⁴⁺ ion exists in the gas.

6. Balancing and checking the equations

Keep product formulas fixed. Balance the Period 3 element and oxygen by changing coefficients, remembering that elemental oxygen is O₂. For Al₂O₃, choose 2Al₂O₃ to give six O atoms, requiring 3O₂ and 4Al. In P₄O₁₀, ten oxygen atoms require five O₂ molecules; four phosphorus atoms are already supplied by P₄.

State symbols describe the substances before/after at the conditions being represented, commonly the cooled solid oxides and SO₂ gas. During burning, particles may be hot or dispersed as fumes; white smoke is suspended condensed material, not a permanently white gas. For sulfur, S(s) is a standard equation convention per mole of S atoms; S₈ notation gives the same elemental balance when coefficients are scaled.

Particle accounting for the balanced aluminium oxygen equationCount atoms without changing the oxide formula4Al + 3O₂ → 2Al₂O₃AlAlAlAl4 Al atomsOOOOOO3 O₂ molecules = 6 O atomsAl₂O₃Al₂O₃2 formula units: 4 Al and 6 O in total
The two product boxes represent amounts of Al₂O₃ composition, not isolated Al₂O₃ molecules. Aluminium oxide has an extended solid structure. The coefficient 2 multiplies both subscripts; changing Al₂O₃ into another formula would describe a different substance.

Worked examples

Example 1 · Derive the sodium equation

Na₂O requires two Na atoms for each O atom. One O₂ supplies two O atoms, so make 2Na₂O and then balance four Na: 4Na + O₂ → 2Na₂O. Check Na 4 and O 2 on each side. This is the specified oxide model.

Example 2 · Balance aluminium without altering Al₂O₃

The lowest common oxygen count for O₂ and Al₂O₃ is 6. Put 3 before O₂ and 2 before Al₂O₃, then 4 before Al: 4Al + 3O₂ → 2Al₂O₃. Check Al 4, O 6 each side. Do not change Al₂O₃ into AlO.

Example 3 · Balance molecular phosphorus

Start P₄ + O₂ → P₄O₁₀. Four P are already balanced. Ten O on the right require five O₂: P₄ + 5O₂ → P₄O₁₀. P₂O₅ gives the empirical ratio, not the specified molecular formula.

Example 4 · Use S₈ consistently

Start S₈ + O₂ → SO₂. Balance S with 8SO₂; this gives sixteen O atoms on the right, requiring 8O₂. Result: S₈ + 8O₂ → 8SO₂. The simpler S + O₂ → SO₂ is a per-S-atom convention, not a different product.

Example 5 · Explain aluminium’s apparent resistance

A bulk sample shows little obvious change while finely divided aluminium can burn after strong heating. An adherent oxide film limits further oxygen access on the bulk surface; higher surface area and suitable initiation enable rapid reaction. Do not conclude that aluminium cannot form an oxide.

Example 6 · Check magnesium’s electron accounting

2Mg + O₂ → 2MgO. Two Mg atoms each change 0 → +2, losing four electrons in total. The two O atoms each change 0 → −2, gaining four. Mg is oxidised and reduces oxygen; O₂ is reduced and is the oxidising agent.

Example 7 · Separate observations from explanation

“Sulfur burns with a blue flame and produces a colourless gas” is an observation. “S forms covalent SO₂ with S at +4 and O at −2” is an explanation. “A white precipitate forms” would describe neither the gaseous SO₂ product nor a correct visible observation here.

Common misconceptions and exam tips

“Every sodium-burning sample is pure Na₂O.” Use the specified model without ignoring real mixtures.
“Aluminium never reacts with oxygen.” Distinguish oxide-film protection from the reaction’s feasibility.
“Sulfur dioxide is white smoke.” SO₂ is a colourless gas; phosphorus oxide gives white smoke.
“Breaking bonds releases the combustion energy.” Bond breaking costs energy; product formation releases it.
“Oxidation number +5 proves P⁵⁺ ions exist.” Covalent substances also use formal oxidation numbers.
“Change subscripts to balance.” Keep the five specified formulas fixed and adjust coefficients.

For an observation question give colour, light/flame and physical product. For an explanation name the bonding or kinetic factor. For an equation include O₂, the required product and a final atom-count check. Avoid a simplistic flame-brightness ranking of reactivity.

Your revision summary

The specified products are Na₂O, MgO, Al₂O₃, P₄O₁₀ and SO₂. All five oxygen reactions are redox and exothermic overall. Metallic ionic-lattice descriptions give way to covalent non-metal oxides; surface films, particle size, allotrope and activation energy influence observations. Balance coefficients while retaining the specified formulas.

Check your understanding

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Question 1 of 5 · Unit 2 C1.3.1

Which is the balanced equation for sodium forming the specified Na₂O product?

Question 2 of 5 · Unit 2 C1.3.1

Why can bulk aluminium appear resistant to oxygen while fine aluminium particles burn after initiation?

Question 3 of 5 · Unit 2 C1.3.1

Which equation correctly forms aluminium oxide?

Question 4 of 5 · Unit 2 C1.3.1

Which observation matches sulfur burning to form the specified oxide?

Question 5 of 5 · Unit 2 C1.3.1

In P₄ + 5O₂ → P₄O₁₀, which statement is correct?

Scope verified against Pearson BTEC Level 3 AAQ Applied Science, Issue 7, May 2026, Unit 2 C1.3.1, printed page 38. Official Pearson specification (PDF).

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